Extract filename only from an absolute path

[Kreatus (Ubot Ninja) 422]

Here is the regex code to extract the filename from full path.

 

extract filename.ubot

 

I got this idea based on franks code here. So thank him for sharing this code. This started a whole lot of ideas.

 

(?!\\).*?(?=\\) will search everything behind \

then replace every \ with nothing. This will leave the filename only...

 

This could be useful for some.

[LoWrIdErTJ - BotGuru 904]

nice.. i was actually doing something like this today and was a lot more difficult process i took.

 

+1

[JohnB 255]

I am not sure of the goal you guys have, or from where you are retrieving file names, but I just wanted make sure you knew the $get files command retrieves files with and without paths.

 

John

[Kreatus (Ubot Ninja) 422]

I am not sure of the goal you guys have, or from where you are retrieving file names, but I just wanted make sure you knew the $get files command retrieves files with and without paths.

 

John

Yes John we are aware of that.. My main goal is to get the variable of uiopenfile filename only and save the file at the end of the bot with additional words in the filename or to save it on other location with the same filename..

 

For example:

 

Original

filename.txt

 

Modified

filename-keywords.txt

filename-url.txt