[SOLVED] Regex Help Needed

[a2mateit 395]

Hi all,

 

Been trying to figure this out on my own but I am stuck.

 

What I am trying to do is remove everything before id in my list of urls.

 

The list looks like this:

http://ezinearticles.com/?UBot-Studio---The-Ultimate-in-Web-Automation?&id=3443164
http://ezinearticles.com/?Build-Your-Own-Software-for-SEO,-Is-It-Possible?&id=6411746

 

What I am needing to do is remove everything before ?&id= and leave the list looking like this:

?&id=3443164
?&id=6411746

 

Or even:

3443164
6411746

 

Any help would be greatly appreciated.

 

Thanks,

Justin

[a2mateit 395]

I have dug around a little bit and this: ^.*?= is supposed to get rid of everything before the =. I just don't know how to implement it in my list to clean all the urls.

[k1lv9h 76]

Hi,

 

Sample code:

set(#urld, "http://ezinearticles.com/?UBot-Studio---The-Ultimate-in-Web-Automation?&id=3443164
http://ezinearticles.com/?Build-Your-Own-Software-for-SEO,-Is-It-Possible?&id=6411746", "Global")
clear list(%urls)
add list to list(%urls, $list from text(#urld, $new line), "Delete", "Global")
loop($list total(%urls)) {
   if($comparison($list position(%urls), "<", $list total(%urls))) {
       then {
           set(#urlitem, $next list item(%urls), "Global")
           set(#urlitemid, $replace regular expression(#urlitem, ".*&id=", $nothing), "Global")
       }
       else {
       }
   }
}

sample-return-id-001.ubot

 

Kevin

[a2mateit 395]

Thanks Kevin,

 

Is there any chance I can remove everything before the "=" while scraping from google?

 

This is the code I am using to scrape from google:

add list to list(%urls, $scrape attribute(<class="l">, "href"), "Delete", "Global")

 

It would really be awesome if you could help me figure that out.

 

Thanks,

Justin

[a2mateit 395]

Nevermind,

 

I got it figured out.

 

Thank you kevin!

[jomark3 25]

using regex:

([0-9]{7})

pulls up just the id number