Expert Regex help me plz

[Sodaubotguru 0]

http://geektyrant.com/storage/0999-post-images/ironyman.jpg%253F__SQUARESPACE_CACHEVERSION%253D1337789008969

http://geektyrant.com/storage/0999-post-images/ironyman.gif%253F__SQUARESPACE_CACHEVERSION%253D1337789008969

 

i would like to get rid of %253F__SQUARESPACE_CACHEVERSION%253D1337789008969 in url how can i solve it

 

some are .gif or .jpg

[Legend 181]

If the numbers are always the same you don't need regex, simple $replace will do it... http://www.ubotstudio.com/forum/public/style_emoticons/default/rolleyes.gif

[CreativeWurks 9]

This isnt the answer, but for most things.... i have chosen to go the route of regexmagic. Id rather let it do the regex for me, and Ill plug it into my tool.

[k1lv9h 76]

Hi,

 

Sample code to do this with regex.

set(#url, "http://geektyrant.com/storage/0999-post-images/ironyman.jpg%253F__SQUARESPACE_CACHEVERSION%253D1337789008969", "Global")
slimdownurl()
set(#url, "http://geektyrant.com/storage/0999-post-images/ironyman.gif%253F__SQUARESPACE_CACHEVERSION%253D1337789008969", "Global")
slimdownurl()
define slimdownurl {
   set(#urlslimmeddown, $replace regular expression(#url, "(%253F_.*)", $nothing), "Global")
   alert(#urlslimmeddown)
}

 

Kevin

[James J 3]

if you want to get rid of everyting behind the % symbol...

i beleive it would it be %.+ in the area where you place

the "text to replace" then put a $nothing parameter or just

leave the "replace with text" empty

 

J