[Solved]Finding Duplicates within a list and saving them to another list

[dmbfan 9]

I've been trying to solve this and just can't seem to figure out how:

 

List 1 contains the values:  Red, Blue, Green, Red, Yellow, Blue, Orange

 

What I am trying to do is identify any duplicate value(s) in List 1 and save those value(s) to List 2

 

In the above example, List 2's values would then be: Red, Blue

 

I am sure there is an easy way to do this, but I think lack of sleep is taking it's toll on me!

[UBotDev 276]

You can do this:

1st use two lists and add all values to both, but use different options (first list shouldn't "delete duplicates" set to YES and the second one to NO)

2nd subtract the list without duplicates from original list, and you will get left with duplicates.

[giganut 109]

I believe you could get the results you are looking for with $common list item

[dmbfan 9]

You can do this:

1st use two lists and add all values to both, but use different options (first list shouldn't "delete duplicates" set to YES and the second one to NO)

2nd subtract the list without duplicates from original list, and you will get left with duplicates.

This was the exact approach I was trying, but it looks like subtract lists subtracts all instances of the duplicate values so it removes all Reds and Blues from the first list and not just one instance of them. I keep getting an empty list as a result...

 

I also played around with common list items using the above approach of creating the multiple files but can't think of a way to make that work because I think that will only returns the non-duplicate items and excluding the ones I actually want.

[giganut 109]

Take a look at TJ's video about filtering lists, this my help you https://www.botguru.net/ubot-studio-tutorials/filtering-lists-remove-from-list-ubot-studio-v4/

[dmbfan 9]

Take a look at TJ's video about filtering lists, this my help you https://www.botguru.net/ubot-studio-tutorials/filtering-lists-remove-from-list-ubot-studio-v4/

Thanks, I think this is the approach that I need to take!  The common list item approach above returns a list of just the unique common items without duplicates of those values.  Thanks again.  I may get to sleep tonight afterall!