Is there a way to extract from a list ?

[webpro 31]

Is there a way to extract from a list, with one item only ?

Or split what's in a list, under one item only ?

 

The problem is, i got a %list which sometimes winds up with 2 urls in it (shows up as one item).

So it's got the same position, which is zero.

Of course, if i navigate to it it doesn't work

http://www.whatever.com/nice.htmhttp://whatever.com/hot.htm

 

I'm trying to find a way to split them or extract one of them from the list.

 

Thanks

[UBotDev 276]

I think you should prevent that from being added to the list initially...so you end up with clean list.

 

However, I think the simplest way to get multiple URLs from a single string is:

add list to list(%URLs, $list from text("http://www.whatever.com/nice.htmhttp://whatever.com/hot.htm", "http://"), "Delete", "Global")

 

 

[webpro 31]

tHANKS uBOTdEV

 

 

Yeah i know but i'm stuck.

I did the best i could with regex to scrape everything but i still get this issue here and then.

 

I'll try this. Tomorrow (i'm dead !!!)

Thanks again

[webpro 31]

Cool this works !

 

Now i need to find a way to tell the bot to navigate from position 1 (if any) as one of the url winds up into position 1 (position 0 still got both urls)

 

I tried:

IF

  $EXISTS

      $LIST ITEM   %URLS2  POSITION #1

THEN

    NAVIGATE

             $LIST ITEM   %URLS2 POSITION #1

 

but i get an INVALID PARAMETER

 

Of course if i try to navigate from position 0

I get both urls mixed up

ex:

http://site.com/http://site2.com

[stanf 43]

Just a suggestion

After your list is biult,run thru the list to clean it up.

If your error is constant "htmhttp" or" htmlhttp" why not code a if/else test?

Set list

Check list = next list item

If checklist contains "htmlhttp"

Spit it in the middle

Else if checklist contains "htmhttp"

Split in the middle

[webpro 31]

Hummm i see

Thanks mate