SaHiN 14 Posted December 8, 2014 Report Share Posted December 8, 2014 Hi, how to make Xpath parser to title and description? <?xml version="1.0" encoding="utf-8"?> <?xml-stylesheet type="text/xsl" href="css/feed.xsl"?> <channel> <title>Sample title 1</title> <description>sample desc 1</description> <item> <title>sample title 2</title> <description>sample desc 2 </description> </item> </channel> Quote Link to post Share on other sites
Gogetta 263 Posted December 9, 2014 Report Share Posted December 9, 2014 Title: alert($plugin function("HTTP post.dll", "$xpath parser", "<?xml version=\"1.0\" encoding=\"utf-8\"?> <?xml-stylesheet type=\"text/xsl\" href=\"css/feed.xsl\"?> <channel> <title>Sample title 1</title> <description>sample desc 1</description> <item> <title>sample title 2</title> <description>sample desc 2</description> </item> </channel>", "//title", "InnerText", "XML")) Description: alert($plugin function("HTTP post.dll", "$xpath parser", "<?xml version=\"1.0\" encoding=\"utf-8\"?> <?xml-stylesheet type=\"text/xsl\" href=\"css/feed.xsl\"?> <channel> <title>Sample title 1</title> <description>sample desc 1</description> <item> <title>sample title 2</title> <description>sample desc 2</description> </item> </channel>", "//description", "InnerText", "XML")) 1 Quote Link to post Share on other sites
SaHiN 14 Posted December 9, 2014 Author Report Share Posted December 9, 2014 Thank you Gogetta 1 Quote Link to post Share on other sites
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