Way to scrape just a part of a url?

[zonfar 1]

There are a bunch of links on a website I am trying to scrape but I want to get rid of the last part of the url. For example this one of the urls: 

 

http://website.com/2134567/thisisatest.avi

 

 

I want to get rid of the"/thisisatest.avi" and all the urls have different titles. Is there any way to delete the ending part so I would end up scraping just

 

http://website.com/2134567

?

 

 

Thanks!

 

EDIT: Just figured out how to do it using the regular scrape page function. I've been spoiled using scrape attribute I forgot all about using regular scrape page haha

[HelloInsomnia 1103]

If there is always a . there like .avi then you can use the file below, if there is not a dot at the end change the regex to this: 

 

\/\w+$

 

http://www.mediafire.com/?rco893i66p0kcf6

 

For some reason the forum wont let me upload the ubot file..

[Aymen 385]

use $replace regular expression

replace "/thisisatest.avi" by "$nothing"

[Randy Role 1]

Try this:  \S+\/