Add 1 To Char Count Position ?

[ATuringtest 14]

This must be simple but I just cant get the syntax

 

I want to add +1 to a position, the variable holds the amount of characters so I can insert or add the next list item to #charCountPos1 but I need to add a space so the two list items are separated.

 

set(#listItem2,$insert text(#listItem2,$next list item(%listList),#charCountPos1),"Global")

 

I could pad the list item but that seems a bit of a waste of code.

 

 

Stay Safe

[ibins 0]

if i get it right, you are looking for

 

increment(#charCountPos1)

 

if not, and if you want to just add some text to a text, you could do it like

 

set(#new,$nothing,"Global")
set(#one,0,"Global")
set(#rand,$rand(3,9),"Global")
loop(#rand) {
    increment(#one)
    set(#addd,$text length(#new),"Global")
    set(#new,$insert text(#new,"{#one}|",#addd),"Global")
}
alert(#new)

[ATuringtest 14]

if i get it right, you are looking for

 

increment(#charCountPos1)

 

if not, and if you want to just add some text to a text, you could do it like

 

set(#new,$nothing,"Global")

set(#one,0,"Global")

set(#rand,$rand(3,9),"Global")

loop(#rand) {

    increment(#one)

    set(#addd,$text length(#new),"Global")

    set(#new,$insert text(#new,"{#one}|",#addd),"Global")

}

alert(#new)

 

Thanks man I'll give it a go

[Pete 121]

set(#charCount,5,"Global")
set(#listItem2,$insert text(#listItem2,$next list item(%listList),$add(#charCount,1)),"Global")

 

[ATuringtest 14]

set(#charCount,5,"Global")
set(#listItem2,$insert text(#listItem2,$next list item(%listList),$add(#charCount,1)),"Global")

 

That's very beautifully simple thanks